Tuesday, 21 October 2014

Attendance on 21-10-2014 for CSE -A & B

Attendance on 21-10-2014 for CSE -A

Class - 2hrs

Absentees: 18, 50

Attendance on 21-10-2014 for CSE -B

DLD Lab

Absentees: - A9, B8

Sunday, 19 October 2014

Attendance on 20-10-2014 for CSE-B

Attendance on 20-10-2014 for CSE-B

Class

Absentees: - 73, 74, 79, 83, 95, 98, A2, A8, B9, LE-03

Saturday, 18 October 2014

Attendance on 18-10-2014 for CSE-B

Attendance on 18-10-2014 for CSE-B

Class

Absentees: - 65, 74, 78, 79, 83, 91, 99, A7, B9, LE-503

Friday, 17 October 2014

Tests on UNIT-2

Tests/Blue book questions on UNIT-2

                                        Click the following link to get the Questions


https://drive.google.com/file/d/0B2SC6jed0s76QklIbk5JdnFsaEU/view?usp=sharing

Assignment - 2

Dear students, You have to submit Assignment -2   after DIWALI otherwise i will give ZERO marks.


                                           Click the following link to get the Questions.



https://drive.google.com/file/d/0B2SC6jed0s76WmZxU0hYcGpIMXM/view?usp=sharing

JNTU Circular about Exams Postpone




Revised TIMETABLE - JNTUK (Mid Exams)

Revised Timetable will be intimated later - JNTUK

Click the following link for Circular
JNTUK_Exam_Postponed.pdf - 455 KB




courtesy :

http://jwfiles.net/uv6j2szs8f5z/JNTUK_Exam_Postponed.pdf.html

Karnaugh Maps - Examples

Karnaugh Maps - Examples




By using the rules of simplification and ringing of adjacent cells in order to make as many variables redundant, the minimised result obtained is B + AC+ 



By using the rules of simplification and ringing of adjacent cells in order to make as many variables redundant, the minimised result obtained is B + A



Introduction to Karnaugh Map


Karnaugh Maps - Rules of Simplification



The Karnaugh map uses the following rules for the simplification of expressions by grouping together adjacent cells containing ones

  • Groups may not include any cell containing a zero
  • Groups may be horizontal or vertical, but not diagonal.
  • Groups must contain 1, 2, 4, 8, or in general 2n cells.
    That is if n = 1, a group will contain two 1's since 21 = 2.
    If n = 2, a group will contain four 1's since 22 = 4.
  • Each group should be as large as possible.
  • Each cell containing a one must be in at least one group.
  • Groups may overlap.
  • Groups may wrap around the table. The leftmost cell in a row may be grouped with the rightmost cell and the top cell in a column may be grouped with the bottom cell.
  • There should be as few groups as possible, as long as this does not contradict any of the previous rules.

Summmary:

  1. No zeros allowed.
  2. No diagonals.
  3. Only power of 2 number of cells in each group.
  4. Groups should be as large as possible.
  5. Every one must be in at least one group.
  6. Overlapping allowed.
  7. Wrap around allowed.
  8. Fewest number of groups possible.


courtesy: http://www.ee.surrey.ac.uk/Projects/Labview/minimisation/karrules.html

A story about Prof. Karnaugh


Maurice Karnaugh


Maurice Karnaugh (born October 4, 1924, in New York City) is an American physicist known for the Karnaugh map used in Boolean algebra.
Karnaugh studied mathematics and physics at City College of New York (1944–48) and transferred to Yale University to complete his B.Sc. (1949), M.Sc. (1950) and Ph.D. in physics with a thesis on The Theory of Magnetic Resonance and Lambda-Type Doubling in Nitric-Oxide (1952).
Karnaugh worked at Bell Labs (1952–66), developing the Karnaugh map (1954) as well as patents for PCM encoding[1]and magnetic logic circuits and coding.[2][3] He later worked at IBM's Federal Systems Division in Gaithersburg (1966–70) and at the IBM Thomas J. Watson Research Center (1970–89), studying multistage interconnection networks.[4]
Karnaugh was elected an IEEE Fellow in 1976, and held an adjunct position at Polytechnic University of New York at the Westchester campus from 1980 to 1999.

He has been married to the former Linn Blank Weil since 1970. He has two grown sons, Robert and Paul, from his first marriage.


courtesy : http://en.wikipedia.org/wiki/Maurice_Karnaugh

ATTENDANCE on 17-10-2014 for CSE-A & B

ATTENDANCE on 17-10-2014 for CSE-A

CLASS -   2hrs


Absentees : - 40, 42, 48




ATTENDANCE on 17-10-2014 for CSE-B

CLASS -   2hrs

Absentees: - 73, 74, 79, 85, 91, 93, A2,  A5,  B1,  B2,  B4, B9, LE-03

Attendance on 16-10-2014 for CSE-A & B

Attendance on 16-10-2014 for CSE-A 

Class

Absentees: 3, 40, 42, 48, 50, 56


Attendance on 16-10-2014 for CSE-B

DLD Lab

Absentees: 70, 79, 81



Attendance on 16-10-2014 for CSE-B

CLASS

Absentees: - 61, 62, 66, 68, 69, 71, 72, 73, 76, 77, 78, 79, 80, 81, 85, 86, 87, 88, 89, 90, 91, 94, 95, 96, 97, 98, 99, A2, A3, A5, A6, A7, A8, B0


Tuesday, 14 October 2014

Attendance on 15-10-2014 for CSE-A

Attendance on 15-10-2014 for CSE-A 

Class

Absentees: - 40

DLD Lab   (1 to 30 batch)

Absentess: - 23

Attendance on 14-10-2014 for CSE-A & B

Attendance on 14-10-2014 for CSE-A

Class

Absentees: 15, 40, 42, 48




Attendance on 14-10-2014 for CSE-B

DLD

Absentees: B9

Monday, 13 October 2014

Memory Units Bits


Memory Units :-
1 Bit = Binary Digit
 8 Bits = 1 Byte
1024 Bytes = 1 Kilo Byte (KB)
1024 KB = 1 MEGA Byte ( MB)
1024 MB = 1 Giga Byte (GB)
1024 GB = 1 Terra Byte (TB)
1024 TB = 1 Peta Byte (PB)
1024 PB = 1 Exa Byte (EB)
1024 EB = 1 Zeta Byte (ZB)
1024 ZB = 1 Yotta Byte (YB)
1024 YB = 1 Bronto Byte (BB)
1024 BB = 1 Geop Byte

De-Morgan Theorems


De-Morgan Theorems

We have known the basic operation of binary arithmetic such as binary addition, binary subtraction, binary multiplication and binary division. Now we will look through the most important part of binary arithmetic on which a lot of Boolean algebra stands, that is De-Morgan's Theorem which is called De-Morgan's Laws often.

Before discussing De-Morgan's theorems we should know about complements. Complements are the reverse value of the existing value. We are trying to say that as there are only two digits in binary number system 0 & 1. Now if A = 0 then complement of A will be 1 or A’ = 1.

There are actually two theorems that were put forward by De-Morgan. On the basis of DE Morgan’s laws much Boolean algebra are solved. Solving these types of algebra with De-Morgan's theorem has a major application in the field of digital electronics. De Morgan’s theorem can be stated as follows:-

Theorem 1:
The compliment of the product of two variables is equal to the sum of the compliment of each variable.
Thus according to De-Morgan's laws or De-Morgan's theorem if A and B are the two variables or Boolean numbers. Then accordingly
(A.B)’ = A’ + B’

Theorem 2:
The compliment of the sum of two variables is equal to the product of the compliment of each variable.
Thus according to De Morgan’s theorem if A and B are the two variables then.
(A + B)’ = A’.B’
De-Morgan's laws can also be implemented in Boolean algebra in the following steps:-
(1) While doing Boolean algebra at first replace the given operator. That is if (+) is there then replace it with (.) and if (.) is there then replace it with (+).
(2) Next compliment of each of the term is to be found.

De-Morgan's theorem can be proved by the simple induction method from the table given below.
1
2
3
4
5
6
7
8
9
10
A
B
A’
B
A+B
A.B
(A+B)’
A’.B’
(A.B)’
A’+B’
0
0
1
1
0
0
1
1
1
1
0
1
1
0
1
0
0
0
1
1
1
0
0
1
1
0
0
0
1
1
1
1
0
0
1
1
0
0
0
0
Now look at the table very carefully in each row. Firstly the value of A = 0 and the value of B = 0. Now for this values A’ = 1, B’ = 1. Again A+B = 0 and A.B = 0. Thus (A+B)’ = 1 and (A.B)’ = 1, A’ + B’ = 1 and A’.B’ = 1. From this table you can therefore see that the value of column no 7 and 8 are equal and column no 9 and 10 are also equal which proves the De-Morgan's theorem.
Again different values of A and B we see the same thing i.e. column no 7 and 8 are equal to each other and 9 and 10 are equal to each other. Thus by this truth table we can prove De-Morgan's theorem.

Some examples given below can make your idea clear.
Let, Solve AB + A’ + B’
AB + A’ + B’
= AB + (AB)’ [since accordingly (AB)' = A' + B' which is a De-Morgan's law]
= 1 [as in Boolean algebra A+A’=1]
Therefore, AB + A’ + B’ = 1. With the help of De-Morgan's theorem our calculation become much easier.





A story about Prof. De-Morgan

Prof. Augustus De Morgan


Augustus De Morgan (27 June 1806 – 18 March 1871) was a British mathematician and logician. He formulated De Morgan's laws and introduced the term mathematical induction, making its idea rigorous.


Beyond his great mathematical legacy, the headquarters of the London Mathematical Society is called De Morgan House and the student society of the Mathematics Department of University College London is called the August De Morgan Society.

De Morgan proceeds to give an inventory of the fundamental symbols of algebra, and also an inventory of the laws of algebra. The symbols are 0, 1, +, −, ×, ÷, ()(), and letters; these only, all others are derived. His inventory of the fundamental laws is expressed under fourteen heads, but some of them are merely definitions. The laws proper may be reduced to the following, which, as he admits, are not all independent of one another:
1.     Law of signs. + + = +, + − = −, − + = −, − − = +, × × = ×, × ÷ = ÷, ÷ × = ÷, ÷ ÷ = ×.
2.     Commutative law. a+b = b+aab=ba.
3.     Distributive law. a(b+c) = ab+ac.
4.     Index laws. ab×ac=ab+c, (ab)c=abc(ab)dad×bd.
5.     aa=0, a÷a=1.

Attendance on 13-10-2014 for CSE-A & B


Attendance on 13-10-2014 for CSE-A 

DLD Lab  (530 to 560 batch)

Absentees: 40, 41, 42, 46, 48


Attendance on 13-10-2014 for CSE-B

Class

Absentees:74, 78, 79, A3, B3, B8, B9, LE-3

Saturday, 11 October 2014

Attendance on 11-10-2014 for CSE-A & B

Attendance on 11-10-2014 for CSE-A

CLASS - 2Hrs

Absentees: 1, 25, 40, 41, 42, 48, 50, 56, 57



Attendance on 11-10-2014 for CSE-B

CLASS 

Absentees: 62, 73, 79, 80, 90, 93, A3, B2, B3, B4, B9, LE-03